Hasnat Kabir

 #include <stdio.h> #include <stdlib.h> int main() { char str[100]; int i; int space=0;     printf("Enter a string\n");     fgets(str,sizeof(str),stdin);     i=0;     while(i<=str[i]){  if(str[i]==' '){         space++;     }     i++; } printf("Total word count :%d" ,space+1);       return 0; }

A. YES or YES?   There is a string  s �  of length  3 3 , consisting of uppercase and lowercase English letters. Check if it is equal to " YES " (without quotes), where each letter can be in any case. For example, " yES ", " Yes ", " yes " are all allowable. Input The first line of the input contains an integer  t �  ( 1 ≤ t ≤ 10 3 1 ≤ � ≤ 10 3 ) — the number of testcases. The description of each test consists of one line containing one string  s �  consisting of three characters. Each character of  s �  is either an uppercase or lowercase English letter. Output For each test case, output " YES " (without quotes) if  s �  satisfies the condition, and " NO " (without quotes) otherwise. You can output " YES " and " NO " in any case (for example, strings " yES ", " yes " and " Yes " will be recognized as a positive response). Example input Copy 10 YES yES yes Yes YeS Noo orZ yEz Y...