935 A. Fafa and his Company solution

1. #include<iostream>
2. using namespace std;
3. int main()
4. {
5. int n;cin>>n;
6. int ans =0,em=0,lr=0,i;
7. for(i=1;i<n;i++)
8. {lr=i;
9. em= n-i;
10. if(lr+em==n and em%lr==0) ans++;
11. }
12.  
13. cout<<ans;
14. return 0; }