1348A. Phoenix and Balance

  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. int main()
  4. {
  5. int n,t,p,s=0,sum=0;
  6. int i;
  7. cin>>t;
  8. while(t--){
  9. cin>>n;
  10. for(i=1;i<=n/2-1;i++)
  11. sum=sum+pow(2,i);
  12. sum =sum+pow(2,n);
  13. for(i=n/2; ;i++)
  14. {s=s+pow(2,i) ;
  15. if(i==n-1)break;}
  16.  
  17.  
  18. cout<<abs(s-sum)<<endl;
  19. s=0;
  20. sum=0;}
  21. return 0;}

Comments

Popular posts from this blog

Codeforce Problem 1703A. YES or YES?

1535A. Fair Playoff

Aptitude test assistant programmer 2018